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This must have been asked before. In a tournament group of four, how many outcomes (permutations) are there?
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I count 12 presuming no ties.
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What do you mean by "outcomes"?
Dave.
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The different results that can occur in a group, for example: A - 12, B - 6, C - 4, D - 2. (Sorry to be vague but I wasn't very good at maths in school - half the lessons were good but the other 60% I didn't understand).
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Each player plays 3 games as white and can score 0.1.2.3.4.5or 6 In these games. There are 4 players that gives 24 possiblities. When we list all the possiblities of all 4 players with white we discover that all possible score as black have already been listed.
There are 24 possible outcomes.
If you only care about order of finish, you can list the 24 possible outcomes and subtract the number of outcomes that are duplicates in order of finish. For example A scorses 12 and A scores 11 both have A as clear first and would only count as 1 outcome.
However if you are interested in the probabilities (assuming white wins, black wins draw have equal chance in each game) You must remember that number of ways each result can happen. A 12 points and a!!points are 2 ways A is clear first.
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Thanks! I think I got that.
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